Упростить: V12+V27/5V3

Ну тут если V-корень и пример выглядит V12+V27/5V3 а не (V12+V27)5V3 То: V12+V27/5V3=(V12*5V3+V27)/5V3=(5V12*3+V27)/5V3=(5V36+V27)/5V3= =(5*6+V27)/5V3=(30+V27)/5V3=(30+V3*9)/5V3=(30+3V3)/5V3=3(10+V3)/5V3 А если (V12+V27)/5V3 то: (V12+V27)/5V3=(V4*3+V3*9)/5V3=(2V3+3V3)/5V3=5V3/5V3=1 Но не как: V39:5:V339 мы получили V12+V27   

[latex]sqrt{12}+frac{sqrt{27}}{5sqrt{3}}=frac{sqrt{12}cdot5sqrt{3}+sqrt{27}}{5sqrt{3}}= frac{sqrt{12}cdotsqrt{75}+sqrt{27}}{5sqrt{3}}=frac{sqrt{900}+sqrt{27}}{5sqrt{3}}=[/latex]   [latex]frac{30+3sqrt{3}}{5sqrt{3}}=frac{3(10+sqrt{3})}{5sqrt{3}}[/latex] ==================================================================== [latex]frac{sqrt{12}+sqrt{27}}{5sqrt{3}}=frac{2sqrt{3}+3sqrt{3}}{5sqrt{3}}=frac{5sqrt{3}}{5sqrt{3}}=1[/latex]