Решите,пожалуйста!!!!Времени нет,нужна помощь

А(2x+1)/(2x-1)-(6x-3)/7(2x+1)-8/(2x-1)(2x+1)=07(2x-1)(2x+1)≠0⇒x≠1/2,x≠-1/2(2x+1)(14x+7)-(6x-3)(2x-1)-8*7=08x²+14x+14x+7-12x²+6x+6x-3-56=0-4x²+40x-52=0x²-10x+13=0D=100-52=48x1=(10-4√3)/2=5-2√3 U x2=5+2√3бy/(y-3)(y+3) -1/y(y+3) +3/2y(y+3)=02y(y-3)(y+3)≠0⇒y≠0,y≠3,y≠-3y*2y-2(y-3)+3*(y-3)=02y²-2y+6+3y-9=02y²+y-3=0D=1+24=25y1=(-1-5)/4=-1,5U y2=(-1+5)/4=1в(2y-1)/7y(2y+1) +8/3(2y-1)(2y+1)=(2y+1)/3y(2y-1)21y(2y-1)(2y+1)≠0⇒y≠0,y≠1/2,y≠-1/2(2y-1)(6y+3)+8*7y=(2y+1)*(14y+7)12y²+6y-6y-3+56y-28y²-14y-14y-7=0-16y²+28y-10=08y²-14y+5=0D=196-160=36y1=(14-6)/16=1/2 U y2=(14+6)/16=5/4г3/(x-3)(x+3) -1/(x-3)²=3/2x(x+3)2x(x-3)²(x+3)≠0⇒x≠0,x≠3,x≠-36x(x-3)-2x(x+3)=3*(x-3)²6x²-18x-2x²-6x-3x²+18x-27=0x²-6x-27=0x1+x2=6 U x1*x2=-27x1=-3 не удов услx2=9д(9x+12)/(x-4)(x²+4x+16) -1/(x²+4x+16)=1/(x-4)x³-64≠0⇒x³≠64⇒x≠49x+12-x+4-x²-4x-16=0-x²+4x=0-x(x-4)=0x=0x=4 не удов усле3/(2y+1)(4y²-2y+1) -1/(2y+1)=(y+3)/(4y²-2y+1)8y³+1≠0⇒8y³≠-1⇒y³≠-1/8⇒y≠-1/23-4y²+2y-1-2y²-6y-y-3=0-6y²-5y-1=06y+5y+1=0D=25-24=1y1=(-5-1)/12=-1/2 не удов услy2=(-5+1)/12=-1/3ж32/[x²(x-2)-(x-2)]+1/(x-1)(x-2)=1/(x+1)32/(x-1)(x+1)(x-2)-(x-2)]+1/(x-1)(x-2)=1/(x+1)(x-1)(x+1)(x-2)≠0⇒x≠1,x≠-1,x≠232+x+1-x²+3x-2=0-x²+4x+31=0x²-4x-31=0D=16+124=140x1=(4-2√35)/2=2-√35 U x2=2+√35з1/3(x-4)+1/2(x²+3)+1/[x²(x-4)+3(x-4)]=01/3(x-4)+1/2(x²+3)+1/2(x²+3)(x-4)=06(x²+3)(x-4)≠0⇒x≠42(x²+3)+3(x-4)+6=02x²+6+3x-12+6=02x²+3x=0x(2x+3)=0x=0x=-1,5