Найдите корни уравнения 40+16х-2/х^2-5/х^3=0

40+16x-2/x²-5/x³=0  |×x³                        ОДЗ: х²≠0   х³≠0   х≠040x³+16x⁴-2x-5=016x⁴+40x³-2x-5=0x₁=0,516x⁴+40x³-2x-5   |_x-0,5_16x⁴-8x³                | 16x³+48x²+22x+10------------            48x³-2x            48x³-24x²            ------------                     22x²-2x                     22x²-12x                     ------------                               10x-5                               10x-5                                -------                                        016x³+48x²+22x+10=0x₂=-2,516x³+48x²+22x+10  |_x+2,5_16x³+40x²                  | 16x²+8x+2------------              8x²+22x              8x²+20x             ------------                        2x+10                        2x+10                        --------                                  016x²+8x+2=0    |÷28x²+4x+1=0     D=-16  ⇒  Уравнение не имеет действительных корней.Ответ: х₁=0,5     х₂=-2,5.