Как можно это преобразовать?

Z =a+biz=sin3π/4 +i +icos3π/4 =sin3π/4 +(1 +cos3π/4)i   || a=sin3π/4 ; b=sin3π/4 || r =√(sin²3π/4 +(1 +cos3π/4)²) =√(sin²3π/4 +1 +cos²3π/4+2cos3π/4) =√(2-√2) ; tqα =(1 +cos3π/4)/sin3π/4 =(1-√2 /2)/√2 /2 =(√2 - 1) ;α =arctq(√2 - 1) .z =√(2-√2) e^(iα)------- sin3π/4 +i +icos3π/4 =sinπ/4 +i- icosπ/4 =√2 /2  +(1 -√2 /2) i   = (√2-√2)  +(1 -√2 /2) i  = (√(2-√2) (cosα +isinα)  ; tqα =(1 -√2 /2) / √2 /2 =(√2 - 1).