Решите пожалуйста 5 заданий

1. sin^2 x = 0,9cos^2 x = 1 - sin^2 x = 1 - 0,9 = 0,111 - 99cos^2 x = 11 - 99*0,1 = 11 - 9,9 = 1,12. tg a = 2; 1/cos^2 a = 1 + tg^2 a = 1 + 4 = 5cos^2 a = 1/5; sin^2 a = 1 - cos^2 a = 1 - 1/5 = 4/5a ∈ [pi; 2pi], поэтому sin a < 0sin a = -2/√5sin a / (√5) = -(2/√5) / (√5) = -2/53. sin (33pi/4) = sin (32pi/4 + pi/4) = sin (pi/4) = √2/2cos (34pi/3) = cos (30pi/3 + 4pi/3) = cos (4pi/3) = -cos (pi/3) = -1/2√32*sin (33pi/4)*cos (34pi/3) = 4√2*√2/2*(-1/2) = -4/2*(√2*√2)/2 = -24. Формулы синуса и косинуса двойных углов:sin 2a = 2sin a*cos a; cos 2a = 2cos^2 a - 1Подставляем в пример1 - 2cos^2 (111) = -cos (222) = -cos (180 + 42) = cos 42cos^2 (114) = cos^2 (180 - 66) = (-cos 66)^2 = cos^2 (66)10cos^2 (66)*tg (66) = 10cos^2 (66)*sin (66)/cos (66) = = 10cos (66)*sin (66)  = 5sin (132) = 5sin (90 + 42) = 5cos 42Получаем[1 - 2cos^2 (111)] / [10cos^2 (114)*tg (66)] = cos 42 / (5cos 42) = 1/5