Помогите решить.) ^- это если что корень. 3.sin^2 x + 6sin x cos x + 8 cos^2 x = 0 5.2cos^2 x – 11sin 2x = 12 6.2sin^2 x – 3sin 2x – 4cos 2x = 4

3. sin^2 x + 6sin x cos x + 8 cos^2 x = 0/cos²xtg²x+6tgx+8=0tgx=aa²+6a+8=0a1+a2=-6 U a1*a2=8a1=-4⇒tgx=-4⇒x=-arctg4+πk,k∈za2=-2⇒tgx=-2⇒x=-arctg2+πn,n∈z5. 2cos^2 x – 11sin 2x = 122cos²x-22sinxcosx-12sin²x-12cos²x=0/cos²x12tg²x+22tgx+10=06tg²x+11tgx+5=0tgx=a6a²+11a+5=0D=121-120=1a1=(-11-1)/12=-1⇒tgx=-1⇒x=-π/4+πn,n∈za2=(-11+1)/12=-5/6⇒tgx=-5/6⇒x=-arctg5/6+πk,k∈z6. 2sin^2 x – 3sin 2x – 4cos 2x = 4 2sin²x-6sinxcosx-4cos²x+4sin²x-4sin²x-4cos²x=0/cos²x2tg²x-6tgx-8=0tg²x-3tgx-4=0tgx=aa²-3a-4=0a1+a2=3 U a1*a2=-4a1=-1⇒tgx=-1⇒x=-π/4+πk,k∈za2=4⇒tgx=4⇒x=arctg4+πn,n∈z