(3х-2)(х +3)≥2х(2 степінь)+ 12

[latex](3x-2)( x^{2} x+3) geq 2 x^{2} +12 \ 3 x^{2} +9x-2x-6 geq 2 x^{2} +12\ 3 x^{2} +7x-6-2 x^{2} -12 geq 0 \ x^{2} +7x-18 geq 0 \ x^{2} +7x-18=0\ D=49+72=121 \ sqrt{D} =11 \ x_{1} = frac{-7+11}{2} =2 \ x_{2} = frac{-7-11}{2}=-9\ \ xin (-infty ;-9]cup[2;+ infty) [/latex]