Арифметическое прогрессия а1+а2+а3=27 а1^2+а2^2+а3^2=275 а1,а2,а3-?

[latex]a_{1}+a_{1}+d+a_{1}+2d=27\ a_{1}^2+(a_{1}+d)^2+(a_{1}+2d)^2=275\\ 3a_{1}+3d=27\ a_{1}+d=9\ a_{2}=9\\ a_{1}^2+(a_{1}+2*(9-a_{1}))^2=194\ a_{1}^2+(18-a_{1})^2=194\ 2a_{1}^2+324-36a_{1}=194\ 2a_{1}^2-36a_{1}+130=0\ a_{1}^2-18a_{1}+65=0\ D=324-4*1*65=8^2\ a_{1}=frac{18+8}{2}=13\ a_{1}=frac{18-8}{2}=5\ a_{1}=13; d=-4\ a_{1}=5; d=4\\ a_{2}=9\ a_{3}=5\ a_{2}=9\ a_{3}=13[/latex]